3x^2+55x-1500=0

Solution for 3x^2+55x-1500=0 equation:

3x^2+55x-1500=0

a = 3; b = 55; c = -1500;
Δ = b2-4ac
Δ = 552-4·3·(-1500)
Δ = 21025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{21025}=145$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-145}{2*3}=\frac{-200}{6}
=-33+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+145}{2*3}=\frac{90}{6}
=15
$